Bridge players tend to use the French derived names Pik, Coeur, Karo and Treff for spades, hearts, diamonds and clubs respectively. The French suits have two sets of names in German - one derived from the French suit names and one purely German set.
#Card game skat plus
In the north and west of Germany, German suited cards are practically unknown, and games are played with French suited cards, which come in packs of 32 cards, 24 cards or 52 cards plus jokers. Each region has its own distinctive pattern, variously available in 32, 36, 24 and 48 card forms (the 48 card pack being a doubled 24 card pack). German suited cards with suits of acorns ( Eichel), leaves ( Gras or Grün), hearts ( Herz or Rot) and bells ( Schellen) are in general use in the south and south-east (Bayern, Sachsen, Thüringen, parts of Baden-Württemberg). Pretty slim.This short survey of German games is at present arranged according to the type of cards used. So, the probability of all 7 cards being in a single hand are 2 in 128, or 1 in 64, which is a 1.56% chance. Of those 128 arrangements, only two of them (all 7 cards in player A's hand and all 7 cards in player B's hand) give you the 7-0 split that you're looking for. The total number of ways that the cards can be distributed between two players is 2 7 (two to the seventh power), which is 128 different arrangements. If so, then what you're trying to figure out is the likelihood of a 7-0 split instead of 6-1, 5-2 or 4-3. If I understand the problem correctly, you're saying that you know for sure that all 7 of the green cards are split somewhere between player A's and player B's hands you just want to know how likely is it that all 7 of them ended up in one of those hands. So my question is: What is the probability that one of the other two players gets the remaining 7 green cards out of a total of 20 cards when drawing ten times (and conversely, what is the chance of him not drawing a single green card, which would result in his partner having all 7 green cards)?Įdit: Apparently I was wrong about this. The only way for my friend to lose the game in our game state was that one player had to have the other 7 cards of the green suit, because the green 8 my friend had was the only weakness to his hand.
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In this particular game, my friend was playing a Null (germ.: zero), where your goal is to actually not make a single trick. Each player is dealt 10 cards which form their hand with two cards set aside that form the so called "Skat" - the player who wins the bidding gets access to these two cards and may exchange one, both, or none of them for cards in their hand, and then setting them aside again. You play a game of Skat with a deck of 32 cards, consisting of eight cards for each of the respective four suits. Before playing each hand, it is decided through bidding who gets to call a game - the other two players form a party playing against that player. So Skat is a three player game of making tricks over the course of ten rounds by playing one of the ten cards from your hand every round. Since we couldn't figure out the math ourselves, I thought some of you math-savvy guys here might be able to solve it for us :) EDIT: Typo in the title, it's supposed to be seven cardsĪ couple of my friends and myself were playing the German card game Skat tonight, and came across a probability problem when trying to calculate the probability of losing a game when playing a certain kind of hand.
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